Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

End-of-Course Assessment - Page 968: 48

Answer

$0.16$, or (I)

Work Step by Step

The discriminant of a quadratic equation is equal to $b^2-4ac$, where a is the coefficient of the $x^2$ term, b is the coefficient of the x term and c is the constant number. To have one real solution, the discriminant should equal 0. If it is $>0$, there are $2$ real solutions, and if it is $<0$, there are $2$ imaginary solutions. $b^2-4ac = 0, (-0.8)^2 - 4*1*c = 0$ Solve for $c$: $ 0.64-4c = 0, 0.64 = 4c, c = 0.16$
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