Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

End-of-Course Assessment - Page 968: 47

Answer

$328$ adult tickets, or (C)

Work Step by Step

We're solving for the number of adult tickets, so let that be $x$. In this case, student tickets would be $x+62$. If there were $4$ times as many adults as child tickets, child tickets would be $0.25x$ We know the total number of tickets is $800$: $x + 0.25x + (x + 62) = 800$ Solve for $x$: $2.25x+62 = 800, 2.25x = 738, x = 328$
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