Answer
$\frac{c}{b}$, or (G)
Work Step by Step
With a c in the denominator of the denominator term and a b in the denominator of the numerator term, we need to multiply the top and bottom by b*c
$\frac{\frac{1}{b} + c}{b + \frac{1}{c}} * \frac{bc}{bc} = \frac{c+bc^2}{b^2c+b} = \frac{c(1+bc)}{b(1+bc)} = \frac{c}{b}$
