Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

End-of-Course Assessment - Page 964: 9

Answer

$\frac{x^2}{2(x-2)}$, or (B)

Work Step by Step

Factor each term, in both numerators and denominators: $\frac{x^3}{x^2-4} * \frac{5x+10}{10x} = \frac{x^3}{(x+2)(x-2)}*\frac{5(x+2)}{10x}$ Cancel out the following: 1. the 5 in the numerator of the second term with the 10 in the denominator (resulting in a 2 on the bottom) 2. The (x-2) terms on the top and bottom 3. The x in the denominator with the $x^3$ in the numerator (resulting in $x^2$ in the top) This equals: $\frac{x^2}{2(x-2)}$
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