Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 8 - Rational Functions - 8-6 Solving Rational Equations - Practice and Problem-Solving Exercises - Page 546: 8

Answer

$x = \dfrac{2}{9}$

Work Step by Step

The least common denominator, or LCD, is $8$, in this case. Convert each fraction to an equivalent one that incorporates the LCD: $\dfrac{2}{8} - \dfrac{8x}{8} = \dfrac{x}{8}$ Add the fractions: $\dfrac{2 - 8x}{8} = \dfrac{x}{8}$ Multiply each side of the equation by $8$ to eliminate the fractions: $-8x + 2 = x$ Subtract $x$ from each side of the equation: $-9x + 2 = 0$ Subtract $2$ from each side of the equation: $-9x = -2$ Divide each side of the equation by $-9$: $x = \dfrac{2}{9}$ To check the solution, plug in $\frac{2}{9}$ for $x$ into the original equation: $\dfrac{1}{4} - \dfrac{2}{9} = \dfrac{\frac{2}{9}}{8}$ Simplify the fractions: $\dfrac{1}{4} - \dfrac{2}{9} = \dfrac{2}{72}$ The LCD of all three fractions is $72$. Convert all fractions to equivalent ones that have $72$ as their denominator: $\dfrac{18}{72} - \dfrac{16}{72} = \dfrac{2}{72}$ Combine like terms: $\dfrac{2}{72} = \dfrac{2}{72}$ Both sides are equal to one another; therefore, this solution is correct.
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