Answer
$(g-f)(x)=x^2-3x-1$
Work Step by Step
Recall:
$(g-f)(x)=g(x)-f(x)$
Use the rule/definition above to obtain:
\begin{align*}
(g-f)(x) &=g(x)-f(x)\\
&=(x^2-1)-3x\\
&=x^2-3x-1
\end{align*}
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 7 - Exponential and Logarithmic Functions - 7-5 Exponential and Logarithmic Equations - Practice and Problem-Solving Exercises - Page 476: 92
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