Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - 7-5 Exponential and Logarithmic Equations - Practice and Problem-Solving Exercises - Page 474: 54

Answer

$x=\frac{1}{3}$

Work Step by Step

We are asked to solve: $\log_{8}{2}=x$ Recall the definition of a logarithm (pg. 451): $\log_{b}{x}=y$ iff $b^y=x$ Applying this definition to our equation (with $b=8, y=x, x=2$), we get: $8^x=2$ Because we know that $2^3=8$ and $\sqrt[3]{8}=2$: $x=\frac{1}{3}$ We confirm that the answer works: $\log_{8}{2}=\frac{1}{3}$ $8^{\frac{1}{3}}=2$ $2=2$
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