Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - 7-5 Exponential and Logarithmic Equations - Practice and Problem-Solving Exercises - Page 474: 50

Answer

$x=-1$

Work Step by Step

Recall the definition of a logarithm (pg. 451): $\log_{b}{x}=y$ iff $b^y=x$ Applying this definition to our equation (with $b=2, y=1/2, x=x$), we get: $\log_{2}{\frac{1}{2}}=x$ $\log_{2}2^{-1}=x$ Next, recall the power property of logarithms (pg. 462): $\log_b{m^n}=n\log_b{m}$ Applying this property, we get: $-1\log_{2}2=x$ $-1\cdot1=x$ (because $2^1=2$) $x=-1$ We confirm that the answer works: $2^{-1}=1/2$ $\frac{1}{2}=\frac{1}{2}$
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