Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Cumulative Standards Review - Multiple Choice - Page 429: 8

Answer

$H$

Work Step by Step

Before we solve this equation, we can see that a $7$ can be factored out: $7(x^2 + 28) = 0$ Divide both sides by $7$: $x^2 + 28 = 0$ Subtract $28$ from both sides of the equation to isolate the $x$ term: $x^2 = -28$ Take the square root of both sides: $x = \sqrt {-28}$ Let's expand the radicand and rewrite it as a product of a square and another number: $x = \sqrt {(-4)(7)}$ We take the square root of $-4$ to take it out from under the radical sign: $x = ± 2i \sqrt {7}$ This corresponds to option $H$.
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