Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Cumulative Standards Review - Multiple Choice - Page 429: 10

Answer

$G$

Work Step by Step

We can see that the $y$ terms for both equations are the same, but in order to get rid of it, we need to make them opposite sign. An easy way to do this is to multiply the whole first equation by $-1$: $-1(4x + 2y) = -1(4)$ Multiply out the terms using distributive property: $-4x - 2y = -4$ Let's now combine the two equations to add them together: $-4x - 2y = -4$ $ 6x + 2y = 8$ Add the two equations to get rid of the $y$ term: $2x = 4$ Divide each side by $2$ to solve for $x$: $x = 2$ Let's plug in this value of $x$ into one of the equations. Let's use the first equation: $4(2) + 2y = 4$ Multiply to simplify: $8 + 2y = 4$ Subtract $8$ from each side to isolate the $y$ term: $2y = -4$ Divide each side by $2$ to solve for $y$: $y = -2$ The solution is $(2, -2)$, which corresponds to option $G$.
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