Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-6 Function Operations - Practice and Problem-Solving Exercises - Page 401: 19

Answer

$\frac{f}{g}(x) = 2x - x^2$ $\text{Domain: all real numbers except } 0$.

Work Step by Step

This exercise asks us to divide one function by another. Let's write out the problem: $\frac{f}{g}(x) =f(x) \div g(x) = \frac{2 - x}{\frac{1}{x}}$ When we divide by a fraction, we multiply by its reciprocal: $\frac{f}{g}(x) =f(x) \div g(x) = (2 - x)(x)$ Multiply: $\frac{f}{g}(x) =f(x) \div g(x) = 2x - x^2$ When we find the domain, we want to find which values of $x$ will cause the function to become undefined; in other words, we want to find any restrictions for $x$ so that we can exclude them from the domain. In this exercise, $\frac{1}{x}$ is undefined when $x=0$, so the domain is any real number except for $0$.
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