Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-6 Function Operations - Practice and Problem-Solving Exercises - Page 401: 18

Answer

$(f \cdot g)(x) = \frac{2}{x} - 1$ $\text{Domain: all real numbers except } 0$.

Work Step by Step

This exercise asks us to multiply the two functions together. Let's write out the problem: $(f \cdot g)(x) = f(x) \cdot g(x) = (2 - x)(\frac{1}{x})$ Distribute the terms: $(f \cdot g)(x) = f(x) \cdot g(x) = (2)(\frac{1}{x}) - (x)(\frac{1}{x})$ Multiply to simplify: $(f \cdot g)(x) = f(x) \cdot g(x) = \frac{2}{x} - \frac{x}{x}$ Simplify the fractions: $(f \cdot g)(x) = f(x) \cdot g(x) = \frac{2}{x} - 1$ When we find the domain, we want to find which values of $x$ will cause the function to become undefined; in other words, we want to find any restrictions for $x$ so that we can exclude them from the domain. In this exercise, $x$ can be any real number except $0$ since $0$ makes $\frac{2}{x}$ undefined.
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