Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-4 Rational Exponents - Practice and Problem-Solving Exercises - Page 388: 107

Answer

$9\sqrt[4] {2}$

Work Step by Step

Before we can add these two numbers, we must transform them so that the radicals are similar. Only then can we perform the operation we are asked to do. Let us expand the radicands in both radicals. For the first radical, the number $162$ can be rewritten as $(81)(2)$, so: $\sqrt[4] {(81)(2)}=\sqrt[4]{3^4(2)}=3\sqrt[4]{2}$ For the second radical, $32=16(2)$ so: $3\sqrt[4] {32}=3\sqrt[4]{16(2)}=3\sqrt[4]{2^4(2)}=3\cdot2\sqrt[4]{2}=6\sqrt[4]{2}$ Finally, we can perform the operation in the original problem because we now have similar radicals and indices for the two terms: $=3\sqrt[4] {2} + 6\sqrt[4] {2}$ $=(3+6)\sqrt[4] {2}$ $=9\sqrt[4]{2}$
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