Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-4 Rational Exponents - Practice and Problem-Solving Exercises - Page 388: 109

Answer

$(x+ 2)^2$

Work Step by Step

To factor a quadratic polynomial in the form $x^2 + bx + c$, we look at factors of the product of $c$ such that, when added together, equal $b$. For the equation $x^2 + 4x + 4 = 0$, $c=4$, so look for factors of $4$ that when added together will equal $4$. This means that we need two positive factors. We came up with the following possibilities: $4=(4)(1)$ $4+1 = 5$ $4=(2)(2)$ $2+2 = 4$ The second pair, $2$ and $2$ is what we are looking for. This means that the factored form of the trinomial is: $$(x + 2)(x + 2)$$ The above expression can be rewritten as: $$(x+ 2)^2$$
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