Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-4 Rational Exponents - Practice and Problem-Solving Exercises - Page 387: 84

Answer

$\dfrac{x^{\frac{3}{4}}y^{\frac{1}{6}}}{xy}$

Work Step by Step

When one exponential term is divided by another exponential term with the same base, subtract the exponents, keeping the base as-is: $\left(x^{\frac{1}{2} - \frac{3}{4}}\right) \cdot \left(y^{-\frac{1}{3} - \frac{1}{2}}\right)$ Before subtracting the fractional exponents, convert fractions such that they have the same denominator: $\left(x^{\frac{2}{4} - \frac{3}{4}}\right) \cdot \left(y^{-\frac{2}{6} - \frac{3}{6}}\right)$ Subtract the exponents: $x^{-\frac{1}{4}} \cdot y^{-\frac{5}{6}}$ Get rid of negative exponents by moving the exponential term to the denominator, changing the exponent from negative to positive: $\dfrac{1}{x^{\frac{1}{4}} \cdot y^{\frac{5}{6}}}$ Do not leave fractional exponents in the denominator. To get rid of negative exponents in the denominator, multiply both numerator and denominator by a factor that will make the denominator have non-fractional exponents. In this case, the factors will be $x^{\frac{3}{4}}$ and $y^{\frac{1}{6}}$: $\dfrac{x^{\frac{3}{4}} \cdot y^{\frac{1}{6}}}{x^{\frac{1}{4}} \cdot y^{\frac{5}{6}} \cdot x^{\frac{3}{4}}\cdot y^{\frac{1}{6}}}$ When one exponential term is multiplied with another exponential term with the same base, add the exponents, keeping the base as-is: $\dfrac{x^{\frac{3}{4}}y^{\frac{1}{6}}}{x^{\frac{4}{4}} y^{\frac{6}{6}}}$ Simplify fractional exponents: $\dfrac{x^{\frac{3}{4}}y^{\frac{1}{6}}}{xy}$
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