Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-3 Binomial Radical Expressions - Practice and Problem-Solving Exercises - Page 380: 79

Answer

$7x^2\sqrt[]{2}$

Work Step by Step

Using $\sqrt[n]{x}\cdot\sqrt[n]{y}=\sqrt[n]{xy},$ the given expression, $ \sqrt[]{7x}\cdot\sqrt[]{14x^3} ,$ is equivalent to \begin{align*} & \sqrt[]{7x(14x^3)} \\&= \sqrt[]{98x^4} .\end{align*} Extracting the root of the factors that is a perfect power of the index, the expression above is equivalent to \begin{align*} & \sqrt[]{49x^4\cdot2} \\&= \sqrt[]{(7x^2)^2\cdot2} \\&= 7x^2\sqrt[]{2} .\end{align*} Hence, the simplified form of the given expression is $ 7x^2\sqrt[]{2} $.
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