Answer
$p^5q^5$
Work Step by Step
Recall the basic exponent property (pg. 360):
$(ab)^n=a^nb^n$
Using this property, we get:
$(pq)^5=p^5q^5$
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 6 - Radical Functions and Rational Exponents - 6-3 Binomial Radical Expressions - Practice and Problem-Solving Exercises - Page 380: 89
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