Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-3 Binomial Radical Expressions - Practice and Problem-Solving Exercises - Page 378: 26

Answer

$8+2\sqrt{15}$

Work Step by Step

Using the square of a binomial which is given by $(a+b)^2=a^2+2ab+b^2$ or by $(a-b)^2=a^2-2ab+b^2,$ the given expression, $ (\sqrt{3}+\sqrt{5})^2 ,$ is equivalent to \begin{align*} & (\sqrt{3})^2+2(\sqrt{3})(\sqrt{5})+(\sqrt{5})^2 \\&= 3+2\sqrt{15}+5 \\&= 8+2\sqrt{15} .\end{align*} Hence, the product of the given expression is $ 8+2\sqrt{15} $.
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