Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-3 Binomial Radical Expressions - Practice and Problem-Solving Exercises - Page 378: 23

Answer

$8+4\sqrt{5}$

Work Step by Step

Using the FOIL Method which is given by $(a+b)(c+d)=ac+ad+bc+bd,$ the given expression, $ (3+\sqrt{5})(1+\sqrt{5}) ,$ is equivalent to \begin{align*} & 3(1)+3(\sqrt{5})+\sqrt{5}(1)+\sqrt{5}(\sqrt{5}) \\&= 3+3\sqrt{5}+\sqrt{5}+5 \\&= (3+5)+(3\sqrt{5}+\sqrt{5}) &\left( \text{combine like terms} \right) \\&= 8+4\sqrt{5} .\end{align*} Hence, the product of the given expression is $ 8+4\sqrt{5} $.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.