Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Lesson Check - Page 370: 6

Answer

$x^2\sqrt{3x}$

Work Step by Step

Recall the property (pg. 369): $\dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}=\sqrt[n]{\dfrac{a}{b}}$ (if $\sqrt[n]{a}$ and $\sqrt[n]{b}$ are real numbers and $b\ne 0$) We use this property to simplify the given expression and obtain: $=\sqrt{\dfrac{21x^{10}}{7x^5}}$ $=\sqrt{3x^5}$ $=\sqrt{x^4\cdot 3x}$ $=\sqrt{x^4} \cdot \sqrt[2]{3x}$ $=x^2\sqrt{3x}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.