Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Lesson Check - Page 370: 5

Answer

$\sqrt[3]{3x}$

Work Step by Step

Recall the property (pg. 369): $\dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}=\sqrt[n]{\dfrac{a}{b}}$ (if $\sqrt[n]{a}$ and $\sqrt[n]{b}$ are real numbers and $b\ne 0$) We use this property to simplify the given expression: $=\dfrac{\sqrt[3]{15x^2}}{\sqrt[3]{5x}}$ $=\sqrt[3]{\dfrac{15x^2}{5x}}$ $=\sqrt[3]{3x}$
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