Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 5 - Polynomials and Polynomial Functions - Cumulative Standards Review - Multiple Choice - Page 356: 13

Answer

$x = 6$

Work Step by Step

When $y$ varies directly as $x$, the relationship is represented by an equation in the form $y=kx$ where $k$ is the constant of variation. When $x = -\frac{2}{5}$, then $y = -3$. Substitute these values into $y=kx$ to find the value of $k$: $-3 = k(-\frac{2}{5})$ Multiply both sides by $-\frac{5}{2}$ to solve for $k$: $-3\left(-\frac{5}{2}\right) = k(-\frac{2}{5})\left(-\frac{5}{2}\right)\\ \frac{15}{2}=k$ The direct variation is represent by the equation $y=\frac{15}{2}x$. To find the value of $x$ when $y=45$, substitute $45$ into $y$ to obtain: $45 = \frac{15}{2}x\\ 45\left(\frac{2}{15}\right)=\frac{15}{2}x\left(\frac{15}{2}\right)\\ \frac{90}{15}=x\\ 6=x$
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