Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 5 - Polynomials and Polynomial Functions - 5-7 The Binomial Theorem - Practice and Problem-Solving Exercises - Page 330: 55

Answer

When $y = 9$, then $x = 27$.

Work Step by Step

A direct variation is represented by the equation $y = kx$ where $k$ is the constant of variation. Since $y = 10$ when $x = 30$, substitute these values into $y=kx$ to find the value of $k$: $y=kx\\ 10 = k(30)$ Divide both sides by $30$ to solve for $k$: $k = \frac{10}{30}$ $k = \frac{1}{3}$ Thus, the direct variation is represented by the equation $y=\frac{1}{3}x$. Substitute $y=9$ into the equation above to find the corresponding value of $x$: $y=\frac{1}{3}x\\ 9 = \frac{1}{3}(x)$ Multiply $3$ to both sides to obtain: $3(9) = 3\left(\frac{1}{3}(x)\right)$ 27=x$ Thus, when $y = 9$, then $x = 27$.
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