Answer
$-2$
Work Step by Step
Factor out $-2$ in the numerator to obtain:
$\dfrac{-6-2i}{3+i}=\dfrac{-2(3 + i)}{3 + i}$
Cancel the common factor $3 + i$ to obtain:
$\require{cancel}
=\dfrac{-2(\cancel{3+i)}}{\cancel{3+1}}=-2$
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