Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 5 - Polynomials and Polynomial Functions - 5-3 Solving Polynomial Equations - Practice and Problem-Solving Exercises - Page 302: 71

Answer

$12$

Work Step by Step

Substitute $1$ for $x$ and $-2$ for $y$ in the expression: $=\dfrac{16(1 - 4)(-2 - 2)}{4(1 - 3)(-2)}$ Let us follow order of operations and simplify what is in parentheses first: $=\dfrac{16(-3)(-4)}{4(-2)(-2)}$ Let us multiply from left to right, according to order of operations: $=\dfrac{(-48)(-4)}{(-8)(-2)}$ Multiply once again in both numerator and denominator: $=\dfrac{(192)}{(16)}$ $=12$
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