Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 5 - Polynomials and Polynomial Functions - 5-1 Polynomial Functions - Practice and Problem-Solving Exercises - Page 287: 60

Answer

$C$

Work Step by Step

In a quadratic equation, which takes the form $ax^2 + bx + c = 0$, the discriminant is found within the Quadratic Formula. The Quadratic Formula is given as: $x = \frac{-b ± \sqrt {b^2 - 4ac}}{2a}$, where $a$ is the coefficient of the squared term, $b$ is the coefficient of the linear term, and $c$ is the constant term. The expression $b^2 - 4ac$ within the radical is called the discriminant. The discriminant can determine how many solutions there are and whether the roots are real or imaginary. In this exercise, $a = q$, $b = r$, and $c = s$. Plug these values into the discriminant: $(r)^2 - 4(q)(s)$ Evaluate the exponent first: $r^2 - 4(q)(s)$ Do the multiplication: $r^2 - 4qs$ Answer option $C$ is correct.
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