Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - Get Ready! - Page 191: 6

Answer

$y=\frac{1}{2}x+8$ Refer to the graph below.

Work Step by Step

Plot each point and connect the points using a line. Refer to the graph above. To find the equation of the line, perform the following steps: (1) Solve for the slope $m$ using the formula $m=\dfrac{y_2-y_1}{x_2-x_1}$: \begin{align*} m&=\dfrac{11-9}{6-2}\\\\ m&=\dfrac{2}{4}\\\\ m&=\frac{1}{2} \end{align*} The slope-intercept form of a line's equation is $y=mx+b$ where $m$=slope and $b$=y-intercept. With $m=\frac{1}{2}$, the tentative equation of the line through the two given points is $y=\frac{1}{2}x+b$. (2) To find the value of $b$, substitute the $x$ and $y$ values of the point $(2, 9)$ into the tentative equation above to obtain: \begin{align*} y&=\frac{1}{2}x+b\\ 9&=\frac{1}{2}(2)+b\\ 9&=1+b\\ 9-1&=b\\ 8&=b \end{align*} Therefore, the equation of the line passing through the two given points is: $$y=\frac{1}{2}x+8$$
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