Answer
$(x-7)^2$
Work Step by Step
Using $(a\pm b)^2=a^2\pm2ab+b^2$ or the square of a binomial, the given expression, $
x^2-14x+49
,$ is equivalent to
\begin{align*}
&
(x)^2-2(7x)+(7)^2
\\&=
(x)^2-2(x\cdot7)+(7)^2
\\&=
(x-7)^2
.\end{align*}
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 4 - Quadratic Functions and Equations - Chapter Review - Page 270: 31
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