Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-9 Quadratic Systems - Practice and Problem-Solving Exercises - Page 264: 71

Answer

$x = \dfrac{3}{5}$

Work Step by Step

We are asked to solve this quadratic equation using the Quadratic Formula, which is given as: $x = \dfrac{-b ± \sqrt {b^2 - 4ac}}{2a}$, where $a$ is the coefficient of the squared term, $b$ is the coefficient of the linear term, and $c$ is the constant term. In this exercise, $a = 25$, $b = -30$, and $c = 9$. Plug these values into the Quadratic Formula: $x = \dfrac{-(-30) ± \sqrt {(-30)^2 - 4(25)(9)}}{2(25)}$ $x = \dfrac{-(-30) ± \sqrt {900 - 4(25)(9)}}{2(25)}$ $x = \dfrac{30 ± \sqrt {900 - 900}}{50}$ $x = \dfrac{30 ± \sqrt {0}}{50}$ $x = \dfrac{30 ± 0}{50}$ $x = \dfrac{30}{50}$ $x = \dfrac{3}{5}$
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