Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-6 Complete the Square - Practice and Problem-Solving Exercises - Page 237: 21


$x=-1 \text{ and } x=3$

Work Step by Step

Subtract $4$ from each side: $$x^2-2x-3=0$$ Factor the trinomial: $$(x-3)(x+1)=0$$ Use the Zero-Product Property by equating each factor to zero, then solve each equation to obtain: \begin{align*} x-3&=0 &\text{or}& &x+1=0\\ x&=3 &\text{or}& &x=-1 \end{align*} Thus, the solutions are $x=-1 \text{ and } x=3$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.