Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-6 Complete the Square - Practice and Problem-Solving Exercises - Page 237: 20


$x=12 \text{ and } x=-8$

Work Step by Step

Subtract $100$ from each side: $$x^2-4x-96=0$$ Factor the trinomial: $$(x-12)(x+8)=0$$ Use the Zero-Product Property by equating each factor to zero, then solve each equation to obtain: \begin{align*} x-12&=0 &\text{or}& &x+8=0\\ x&=12 &\text{or}& &x=-8 \end{align*} Thus, the solutions are $x=12 \text{ and } x=-8$.
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