Answer
$x=1$ and $x=7$
Work Step by Step
Put all terms on the left side. Note that when a term is transferred from one side to the other in an equation, its sign changes to its opposite.
$$x^2-8x+7=0$$
Factor the binomial:
$$(x-7)(x-1)=0$$
Use the Zero-Product Property by equating each factor with a variable to zero, then solve each equation to obtain:
\begin{align*}
x-7&=0 &\text{or}& &x-1=0\\
x&=7 &\text{or}& &x=1
\end{align*}
Thus, the solutions are $x=1$ and $x=7$.
