Chapter 4 - Quadratic Functions and Equations - 4-5 Quadratic Equations - Practice and Problem-Solving Exercises - Page 230: 40

$x = -4, -1$

This equation was solved as if the right side had a 0. Factoring and then using the factors to get the solutions can only be done when setting the quadratic expression equal to 0. Solve: $x^2 + 5x + 6 = 2, x^2 + 5x + 4 = 0$ $(x+4)(x+1) = 0, x = -4, -1$