## Algebra 2 Common Core

$10(x+3)(x-3)$
Factoring the $GCF= 10 ,$ the given expression, $10x^2-90 ,$ is equivalent to \begin{align*} 10(x^2-9) .\end{align*} Using the factoring of the difference of $2$ squares which is given by $a^2-b^2=(a+b)(a-b),$ the expression above is equivalent to \begin{align*} & 10[(x)^2-(3)^2] \\&= 10[(x)^2-(3)^2] \\&= 10[(x+3)(x-3)] \\&= 10(x+3)(x-3) .\end{align*}