Answer
$4(n-2)(n-3)$
Work Step by Step
Factoring the $GCF=
4
,$ the given expression, $
4n^2-20n+24
,$ is equivalent to
\begin{align*}
4(n^2-5n+6)
\end{align*}
Using the factoring of trinomials in the form $x^2+bx+c,$ the expression above has $c=
6
$ and $b=
-5
.$
The two numbers with a product of $c$ and a sum of $b$ are $\left\{
-2,-3
\right\}.$ Using these two numbers, the factored form of the expression above is
\begin{align*}
4(n-2)(n-3)
\end{align*}
