Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-3 Modeling With Quadratic Functions - Practice and Problem-Solving Exercises - Page 214: 38

Answer

The solution is $x = -1, y = -1$ or $(-1, -1)$.

Work Step by Step

We want the $x$ terms of both equations to be the same but differing in sign. Let us first multiply the second equation by $-1$: $-x + 2y = -1$ Set up the two equations: $x - 3y = 2$ $-x + 2y = -1$ Add the two equations: $-y = 1$ Divide both sides of the equation by $-1$: $y = -1$ Substitute this value for $y$ into the first equation: $x - 3(-1) = 2$ Multiply to simplify: $x + 3 = 2$ Subtract $3$ from each side of the equation: $x = -1$
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