Answer
A child's ticket would cost $5$ dollars.
Work Step by Step
Let's set up a system of equations.
Let $x$ = the cost of an adult ticket
Let $y$ = the cost of a child's ticket
$4x + 3y = 47$
$2x + 4y = 36$
Let's multiply the second equation by $-2$ so that we can eliminate the $x$ term:
$4x + 3y = 47$
$-4x - 8y = -72$
Let's add the two equations together:
$-5y = -25$
Divide both sides by $-5$:
$y = 5$
Remember that $y$ represents the price of a child's ticket; therefore, a child's ticket would cost $5$ dollars.
