Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - Cumulative Standards Review - Multiple Choice - Page 190: 10

Answer

$20 g$

Work Step by Step

Let's set up a proportion to compare the number of calories present in a certain number of grams of crackers: $\dfrac{80 C}{16 g} = \dfrac{100 C}{x}$ Cross-multiply to eliminate the fractions: $(80 C)(x) = (16 g)(100 C)$ Multiply to simplify: $80x = 1600$ Divide both sides by $80$: $x = 20$ There are $20 g$ in that package of crackers.
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