## Algebra 2 Common Core

$x = -\frac{1}{5}$ $y = \frac{19}{5}$
Equations: $x - y = -4$ $3x +2y = 7$ Making the equations into an equivalent system: $2(x - y)= 2( -4)$ $3x +2y = 7$ $2x - 2y = -8$ $3x +2y = 7$ Add the equations together to eliminate $y$, then solve for $x$: $2x - 2y = -8$ $+$ $3x +2y = 7$ $5x = -1$ $x = -\frac{1}{5}$ Substituting $x$ into the first equation to solve for $y$: $x - y = -4$ $-\frac{1}{5} - y = -\frac{20}{5}$ (Make -4 a fraction to add $x$ which is a fraction) $-y = -\frac{19}{5}$ $y = \frac{19}{5}$