Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - 3-2 Solving Systems Algebraically - Lesson Check: 4

Answer

$x = 5$ $y = -3$

Work Step by Step

Equations: $x + 2y = -1$ $x - y = 8$ Making the equations an equivalent system by multiplying the second equation by 2: $x + 2y = -1$ $2(x - y) = 2(8)$ $x + 2y = -1$ $2x - 2y = 16$ Eliminating $y$ to solve for $x$ $x + 2y = -1$ $+$ $2x - 2y = 16$ $3x = 15$ $x = 5$ Substituting $x$ into the second equation to solve for $y$ $x - y = 8$ $5 - y = 8$ $-y = 3$ $y = -3$
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