Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - 3-1 Solving Systems Using Tables and Graphs - Practice and Problem-Solving Exercises - Page 138: 14

Answer

We bought $3$ one-pound bags of peanuts and $2$ three-pound bags of peanuts.

Work Step by Step

We need to set up a system of equations to find the solution. First, we need to define two variables: $x$ = the number of one-pound bags of peanuts purchased $y$ = the number of three-pound bags of peanuts purchased $5$ bags of peanuts will be bought so $x + y = 5$. One-pound bags of peanuts are $2$ dollars each whereas the three-pound bags are $5.50$ dollars apiece. The total cost is $17$ dollars so $2x + 5.5y = 17$ Let us put the two equations together to solve for $x$ and $y$: $x + y = 5$ $2x + 5.5y = 17$ Let us multiply the first equation by $2$ so that the $x$ terms for both equations can cancel each other out, leaving only the $y$ terms: $2x + 2y = 10$ $2x + 5.5y = 17$ We subtract the second equation from the first equation: $(2x+2y)-(2x+5.5y)=10-17\\ 2x+2y-2x-5.5y=-7\\ -3.5y=-7$ y = \frac{-7}{-3.5}\\ y=2$ We can now use the value for $y$ to substitute into the first equation ($x + y = 5$) to find the value for $x$: $x+y=5\\ x + 2 = 5\\ x=5-2\\ x=3$ We now know that we bought $3$ one-pound bags of peanuts and $2$ three-pound bags of peanuts.
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