Answer
$$\sec\theta=\pm\sqrt{1+\tan^{2}\theta}$$
Work Step by Step
By identity, $\sec^{2}\theta=1+\tan^{2}\theta$.
Taking square root on both sides,
$$\sec\theta=\pm\sqrt{1+\tan^{2}\theta}$$
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 14 - Trigonometric Identities and Equations - 14-1 Trigonometric Identities - Practice and Problem-Solving Exercises - Page 909: 46
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