Answer
$\pm\sqrt {1+cot^{2}\theta}$
Work Step by Step
By Identity, $csc^{2}\theta=1+cot^{2}\theta$.
Taking the square-root on both sides gives:
$$csc\theta=\pm\sqrt{1+cot^{2}\theta}$$
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 14 - Trigonometric Identities and Equations - 14-1 Trigonometric Identities - Practice and Problem-Solving Exercises - Page 909: 44
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