Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 12 - Matrices - 12-3 Determinants and Inverses - Practice and Problem-Solving Exercises - Page 790: 72

Answer

$\dfrac{12!}{6!\text{ }3!}=110880$

Work Step by Step

Using the factorial of a number which is given by $n!=n(n-1)(n-2)...(3)(2)(1),$ the given expression, $ \dfrac{12!}{6!\text{ }3!} ,$ is equivalent to \begin{align*}\require{cancel} & \dfrac{12(11)(10)(9)(8)(7)(6!)}{6!\text{ }3(2)(1)} \\\\&= \dfrac{12(11)(10)(9)(8)(7)(\cancel{6!})}{\cancel{6!}\text{ }3(2)(1)} \\\\&= \dfrac{12(11)(10)(9)(8)(7)}{3(2)(1)} \\\\&= \dfrac{12(11)(10)(\cancel9^3)(8)(7)}{\cancel3(2)(1)} \\\\&= \dfrac{12(11)(10)(3)(\cancel8^4)(7)}{(\cancel2)(1)} \\\\&= 12(11)(10)(3)(4)(7) \\&= 110880 .\end{align*} Hence, $ \dfrac{12!}{6!\text{ }3!}=110880 .$
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