Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 12 - Matrices - 12-3 Determinants and Inverses - Practice and Problem-Solving Exercises - Page 790: 64

Answer

$\dfrac{6!}{8!}=\dfrac{1}{56}$

Work Step by Step

Using $n!=n(n-1)(n-2)...(3)(2)(1),$ the value of the given expression, $ \dfrac{6!}{8!} ,$ is \begin{align*}\require{cancel} & \dfrac{6!}{8(7)(6!)} \\\\&= \dfrac{\cancel{6!}}{8(7)(\cancel{6!})} \\\\&= \dfrac{1}{8(7)} \\\\&= \dfrac{1}{56} .\end{align*} Hence, $ \dfrac{6!}{8!}=\dfrac{1}{56} .$
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