Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 12 - Matrices - 12-2 Matrix Multiplication - Practice and Problem-Solving Exercises - Page 778: 37

Answer

$-3F=\begin{bmatrix} 9 & -6 \\ 15 & -3 \\ -6 & -12 \end{bmatrix}$

Work Step by Step

Multiplying each element of $F= \begin{bmatrix} -3 & 2 \\ -5 & 1 \\ 2 & 4 \end{bmatrix} $ by $-3,$ then \begin{align*} -3F&= \begin{bmatrix} -3(-3) & 2(-3) \\ -5(-3) & 1(-3) \\ 2(-3) & 4(-3) \end{bmatrix} \\\\&= \begin{bmatrix} 9 & -6 \\ 15 & -3 \\ -6 & -12 \end{bmatrix} .\end{align*} Hence, $ -3F=\begin{bmatrix} 9 & -6 \\ 15 & -3 \\ -6 & -12 \end{bmatrix} .$
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