Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 12 - Matrices - 12-1 Adding and Subtracting Matrices - Practice and Problem-Solving Exercises - Page 770: 42


\begin{align*} \text{Slope: }&m=-\dfrac{1}{2} \\y-\text{intercept: }& -6 \end{align*}

Work Step by Step

In the form $y=mx+b,$ the given equation, $ -x-2y=12 ,$ is equivalent to \begin{align*} -x+x-2y&=x+12 \\ -2y&=x+12 \\\\ \dfrac{-2y}{-2}&=\dfrac{x+12}{-2} \\\\ y&=\dfrac{1}{-2}x+\dfrac{12}{-2} \\\\ y&=-\dfrac{1}{2}x-6 .\end{align*} The Slope-Intercept Form of the equation of lines, which is given by $y=mx+b,$ has slope $m$ and $y$-intercept of $b$. With the equation above then \begin{align*} \text{Slope: }&m=-\dfrac{1}{2} \\y-\text{intercept: }& -6 .\end{align*}
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