## Algebra 2 Common Core

In the form $y=mx+b,$ the given equation, $-x-2y=12 ,$ is equivalent to \begin{align*} -x+x-2y&=x+12 \\ -2y&=x+12 \\\\ \dfrac{-2y}{-2}&=\dfrac{x+12}{-2} \\\\ y&=\dfrac{1}{-2}x+\dfrac{12}{-2} \\\\ y&=-\dfrac{1}{2}x-6 .\end{align*} The Slope-Intercept Form of the equation of lines, which is given by $y=mx+b,$ has slope $m$ and $y$-intercept of $b$. With the equation above then \begin{align*} \text{Slope: }&m=-\dfrac{1}{2} \\y-\text{intercept: }& -6 .\end{align*}