Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-1 Permutations and Combinations - Lesson Check: 3


$10$ possible combinations.

Work Step by Step

Using the formula for combinations, $\frac{n!}{r!(n-r)!}$, where $n =$ the size of the set, and $r=$ the size of the combinations. $n = 5$, and $r = 2$ Substitute these values for $n$ and $r$ in the formula: $\frac{5!}{2!(5-2)!}$ Simplify the dominator: $=\frac{5!}{2! \times 3!}$ Expand the factorials: $=\frac{5\times 4 \times 3 \times2 \times 1}{2 \times 1 \times 3 \times2 \times 1}$ Calculate: $\frac{120}{12} = 120 \div 12 = 10$ There are $10$ possible combinations.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.