Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-1 Permutations and Combinations - Lesson Check: 1

Answer

$120$ possible permutations.

Work Step by Step

Using the formula for permutations, $\frac{n!}{(n-r)!}$, $n = 6$ and $r = 3$. Substitute the values for $n$ and $r$: $\frac{6!}{(6-3)!}$ Simplify the denominator: $=\frac{6!}{3!}$ Expand the factorials: $=\frac{6\times 5\times 4 \times 3 \times3 \times 1}{3 \times 2 \times 1}$ Calculate: $\frac{720}{6} = 120$ There are $120$ possible permutations.
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