Answer
$120$ possible permutations.
Work Step by Step
Using the formula for permutations, $\frac{n!}{(n-r)!}$, $n = 6$ and $r = 3$.
Substitute the values for $n$ and $r$:
$\frac{6!}{(6-3)!}$
Simplify the denominator:
$=\frac{6!}{3!}$
Expand the factorials:
$=\frac{6\times 5\times 4 \times 3 \times3 \times 1}{3 \times 2 \times 1}$
Calculate:
$\frac{720}{6} = 120$
There are $120$ possible permutations.
