## Algebra 2 Common Core

$\dfrac{16}{3}$
Distribute 3 to have $6z+3=35$. Subtract $3$ from both sides to have $6z+3-3=35-3 \\6z=32$. Divide both sides by 6 to have $z=\frac{32}{6} \\z=\frac{16}{3}.$